PHYSICS
JAMB 2004 - Question 50
Physics 2004 JAMB Past Questions - Question 50: Given three capacitors 0.3µF ,0.5µF and 0.2µF, the joint capacitance when arranged to give minimum capacitance is
Choose the correct answers from the options given.
A:
B:
C:
D:
Correct Answer
B
Explanation
To find the joint capacitance when capacitors are arranged to give the minimum capacitance, you'll want to connect them in parallel. In a parallel configuration, the total capacitance is the sum of the individual capacitances. So, for the given capacitors:
C_total = C1 + C2 + C3
C_total = 0.3 µF + 0.5 µF + 0.2 µF
C_total = 1.0 µF
So, the total joint capacitance when the capacitors are arranged to give the minimum capacitance is 1.0 µF.
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