MATHEMATICS
JAMB 2011 - Question 16
Mathematics 2011 JAMB Past Questions - Question 16: if x varies directly as square root of y and x=81 when y=9,find x when y=1 7/9
A:
B:
C:
D:
Correct Answer
D
Explanation
If x varies directly as the square root of y, we can write the equation as x = ky^(1/2), where k is the constant of variation.To find the value of k, we can substitute the given values of x and y into the equation:81 = k * 9^(1/2)Taking the square root of 9, we have:81 = k * 3Solving for k, we divide both sides of the equation by 3:k = 81 / 3k = 27Now that we have the value of k, we can use it to find x when y = 1 7/9:x = 27 * (1 7/9)^(1/2)To simplify (1 7/9)^(1/2), we convert the mixed number to an improper fraction:x = 27 * (16/9)^(1/2)Taking the square root of 16/9, we have:x = 27 * (4/3)Simplifying further:x = 27 * 4/3x = 36Therefore, when y = 1 7/9, x = 36.
Frequently Asked Questions
Examkits is a JAMB CBT practice platform that provides over 20 years of past questions, Post UTME questions, and detailed video solutions to help students prepare for their exams.
You can practice JAMB past questions online, on Android, or on a desktop using the Examkits app. Just register on our website and choose your preferred device.
Yes. Our Android and Windows versions support offline usage. Once downloaded and activated, no internet is required to use most of the features.
Yes, Examkits provides detailed video explanations for all JAMB past questions from 2000 to 2024, helping students understand how to solve each problem.
Examkits offers free practice for some subjects. However, full access requires a one-time affordable activation fee for each version of the app.