MATHEMATICS

JAMB 2011 - Question 15

Mathematics 2011 JAMB Past Questions - Question 15: Solve of x and y respectively in the simultaneous equation -2x-5y=3 ,x+3y=0

Solve of x and y respectively in the simultaneous equation -2x-5y=3 ,x+3y=0
A:
B:
C:
D:
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Correct Answer

C

Explanation

- 2x - 5y = 3x + 3y = 0therefore x = -3y- 2 (-3y) -5y = -36y -5y = 3 y = 3 but x = -3y x = -3(3)x = -9therefore x = -9 y = 3To solve the simultaneous equations -2x - 5y = 3 and x + 3y = 0, we can use the method of substitution or elimination. Let's use the method of elimination:Multiply the second equation by 2 to make the coefficients of x in both equations equal:2(x + 3y) = 2(0)2x + 6y = 0Now we have the system of equations:-2x - 5y = 32x + 6y = 0Adding the two equations together eliminates the x term:(-2x - 5y) + (2x + 6y) = 3 + 0y = 3Substituting the value of y back into the second equation:x + 3(3) = 0x + 9 = 0x = -9Therefore, the solution to the simultaneous equations -2x - 5y = 3 and x + 3y = 0 is x = -9 and y = 3.

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