PHYSICS
JAMB 2022 - Question 35
Physics 2022 JAMB Past Questions - Question 35: Calculate the electric yield intensity between two plates of potential difference 6.5V when separated by a distance of 35cm
Choose the correct answers from the options given.
A:
B:
C:
D:
Correct Answer
A
Explanation
To calculate the electric field intensity between two plates of potential difference, you can use the formula:
\[ E = \frac{V}{d} \]
Where:
\( E \) = Electric field intensity (in volts per meter, V/m)
\( V \) = Potential difference (in volts, V)
\( d \) = Distance between the plates (in meters, m)
Given:
\( V = 6.5 \, V \)
\( d = 35 \, cm = 0.35 \, m \)
Now, let's calculate the electric field intensity:
\[ E = \frac{6.5 \, V}{0.35 \, m} \]
\[ E = 18.57 \, V/m \]
So, the electric field intensity between the two plates is \( 18.57 \, V/m \).
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