PHYSICS
JAMB 2021 - Question 4
Physics 2021 JAMB Past Questions - Question 4: A charge of 30μC experiences a force of 60N at a certain point. The electric field intensity due to the charge is
Choose the correct answers from the options given.
A:
B:
C:
D:
Correct Answer
D
Explanation
The electric field intensity (\(E\)) due to a point charge can be calculated using the formula:
\[E = \frac{F}{q}\]
Where:
\(E\) = Electric field intensity
\(F\) = Force experienced by the charge
\(q\) = Magnitude of the charge
In this case, the force experienced by the charge is 60N and the magnitude of the charge is 30μC (which is \(30 \times 10^{-6}\) C).
Plugging these values into the formula:
\[E = \frac{60}{30 \times 10^{-6}} = 2 \times 10^6 N/C\]
So, the electric field intensity due to the charge is \(2 \times 10^6 N/C\).
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