PHYSICS
JAMB 2017 - Question 9
Physics 2017 JAMB Past Questions - Question 9: Calculate the electric field intensity between two plates of potential difference 6.5V when separated by a distance of 35cm.
Choose the correct answers from the options given.
A:
B:
C:
D:
Correct Answer
A
Explanation
Electric field intensity,E = V = 6.5 = 650 = 18.57Nc1 D 0.35 350To calculate the electric field intensity between two plates, we can use the formula:
Electric field intensity (E) = Potential difference (V) / Distance between plates (d)
Given:
Potential difference (V) = 6.5V
Distance between plates (d) = 35cm = 0.35m
Using the formula, we can substitute the given values:
E = 6.5V / 0.35m
Calculating the result:
E ≈ 18.57 V/m
Therefore, the electric field intensity between the two plates is approximately 18.57 V/m.
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