PHYSICS
JAMB 2016 - Question 36
Physics 2016 JAMB Past Questions - Question 36: If the force on a charge of 0.2 coulomb in an electric field is 4N, then the electric field intensity of the field is
Choose the correct answers from the options given.
A:
B:
C:
D:
Correct Answer
B
Explanation
To calculate the electric field intensity (E) of a field, you can use the formula:
E = F / q
where E is the electric field intensity, F is the force exerted on the charge, and q is the magnitude of the charge.
In this case, you have a charge of 0.2 coulomb and a force of 4N. Plugging these values into the formula, we get:
E = 4N / 0.2C
E = 20 N/C
Therefore, the electric field intensity of the field is 20 N/C.
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