PHYSICS
JAMB 2013 - Question 36
Physics 2013 JAMB Past Questions - Question 36: Calculate the force acting on an electron of change 1.5x¹ degree placed in an electric field of intensity 10-v-¹¹.
Choose the correct answers from the options given.
A:
B:
C:
D:
Correct Answer
D
Explanation
To calculate the force acting on an electron in an electric field, we can use the formula:
Force (F) = charge (q) × electric field intensity (E)
Given:
Charge of the electron (q) = 1.6 × 10^-19 C (Coulombs)
Electric field intensity (E) = 10^-11 V/m (Volts per meter)
Substituting the values into the formula, we get:
F = (1.6 × 10^-19 C) × (10^-11 V/m)
Calculating this expression, we find:
F = 1.6 × 10^-19 × 10^-11 C × V/m
= 1.6 × 10^-30 N
Therefore, the force acting on the electron is 1.6 × 10^-30 Newtons.
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