PHYSICS
JAMB 2013 - Question 13
Physics 2013 JAMB Past Questions - Question 13: Calculate the work done when a force of 20N stretches a spring by 50mm.
Choose the correct answers from the options given.
A:
B:
C:
D:
Correct Answer
A
Explanation
Work done in an elastic string=average force x extension, e = 500mm = 0.05m=1/2 x 20 x 0.05 = 10 x 0. 05 = 0.05J
To calculate the work done when a force stretches a spring, we can use the formula:
Work = (1/2) * k * x^2
Where:
- Work is the work done (in joules)
- k is the spring constant (in newtons per meter)
- x is the displacement of the spring (in meters)
In this case, we are given:
- Force = 20 N
- Displacement = 50 mm = 0.05 m
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