PHYSICS
JAMB 2011 - Question 44
Physics 2011 JAMB Past Questions - Question 44: In a circuit , the ratio of r.m.s value to peak value of current is 1
Choose the correct answers from the options given.
A:
B:
C:
D:
Correct Answer
A
Explanation
In an ideal sinusoidal AC (alternating current) circuit, the ratio of the root mean square (r.m.s) value to the peak value of the current is indeed 1. This is because the r.m.s value is defined as the square root of the average of the squares of the instantaneous current values, and in a sine wave, the r.m.s value is directly related to the peak value.
Mathematically, for a sinusoidal current waveform:
r.m.s current (I_rms) = Peak current (I_peak) / √2
So, if you divide the peak current by the square root of 2 (√2), you will get the r.m.s current. The value of √2 is approximately 1.41421356, so in an ideal sinusoidal AC circuit, the ratio of r.m.s current to peak current is approximately 1.
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