PHYSICS
JAMB 2009 - Question 46
Physics 2009 JAMB Past Questions - Question 46: If the decay constant of a radioactive substance is 0.231s^1 , the half-life is
Choose the correct answers from the options given.
A:
B:
C:
D:
Correct Answer
A
Explanation
The half-life (t1/2) of a radioactive substance can be calculated using the decay constant (λ) with the following formula:
t1/2 = ln(2) / λ
where:
- t1/2 is the half-life.
- ln(2) is the natural logarithm of 2, approximately equal to 0.6931.
- λ is the decay constant.
In your case, the decay constant (λ) is 0.231 sâ�»¹. Plugging this value into the formula:
t1/2 = ln(2) / 0.231 s¹
t1/2 ≈ 3.01 seconds
So, the half-life of the radioactive substance with a decay constant of 0.231 s¹ is approximately 3.01 seconds.
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