PHYSICS
JAMB 2006 - Question 39
Physics 2006 JAMB Past Questions - Question 39: The wavelength of the first overtone of a note in a closed pipe of length 33cm is
Choose the correct answers from the options given.
A:
B:
C:
D:
Correct Answer
B
Explanation
To find the wavelength of the first overtone (second harmonic) in a closed pipe, you can use the following formula:
Wavelength (λ) = 2 * L / n
Where:
- λ is the wavelength.
- L is the length of the closed pipe.
- n is the harmonic number.
In this case, you're looking for the first overtone (second harmonic), so n = 2, and the length of the closed pipe is given as 33 cm.
Wavelength (λ) = 2 * 33 cm / 2
Wavelength (λ) = 33 cm
So, the wavelength of the first overtone of a note in a closed pipe with a length of 33 cm is 33 cm.
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