PHYSICS
JAMB 2005 - Question 15
Physics 2005 JAMB Past Questions - Question 15: If two inductors of inductances 3H and 6H are arranged in series, the total inductance is
Choose the correct answers from the options given.
A:
B:
C:
D:
Correct Answer
C
Explanation
L=L1+L2=3+6=9HWhen inductors are arranged in series, their total inductance (L_total) is not simply the sum of their individual inductances. Instead, you calculate it as follows:
1 / L_total = 1 / L1 + 1 / L2
In your case, L1 is 3 H (henries) and L2 is 6 H.
1 / L_total = 1 / 3 + 1 / 6
Now, find a common denominator to simplify the equation:
1 / L_total = 2/6 + 1/6
1 / L_total = 3/6
Now, add the fractions on the right side:
1 / L_total = 1/2
To isolate L_total, take the reciprocal of both sides:
L_total = 2 H
So, when two inductors of 3 H and 6 H are arranged in series, the total inductance is 2 H.
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