PHYSICS
JAMB 2002 - Question 43
Physics 2002 JAMB Past Questions - Question 43: The energy associated with the photon of a radio transmission at 3 x 105Hz is [h = 6.63 x 10-34Js]
Choose the correct answers from the options given.
A:
B:
C:
D:
Correct Answer
D
Explanation
Energy=hF=6.63*10-34*3*105=1.989*10-28JThe energy of a photon can be calculated using the formula:
E = h * f
Where:
E is the energy of the photon (in joules),
h is Planck's constant, approximately 6.626 x 10^-34 joule-seconds,
f is the frequency of the photon (in hertz).
In your case, the frequency (f) is 3 x 10^5 Hz. Plugging in these values into the formula:
E = (6.626 x 10^-34 J·s) * (3 x 10^5 Hz)
E ≈ 1.9878 x 10^-28 joules
So, the energy associated with a photon of a radio transmission at a frequency of 3 x 10^5 Hz is approximately 1.9878 x 10^-28 joules.
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