PHYSICS
JAMB 2002 - Question 18
Physics 2002 JAMB Past Questions - Question 18: The pressure of 3 moles of an ideal gas at a temperature of 27°C having a volume of 10-³m³ is
Choose the correct answers from the options given.
A:
B:
C:
D:
Correct Answer
B
Explanation
PV/T =nR;P*10-3/27+273 =3*8.3P=7.47*106N/M2To find the pressure of 3 moles of an ideal gas at a temperature of 27°C with a volume of 10^-3 m³, you can use the ideal gas law:
\[PV = nRT\]
Where:
P = Pressure (in pascals, Pa)
V = Volume (in cubic meters, m³)
n = Number of moles
R = Universal gas constant (8.314 J/(mol·K))
T = Temperature (in kelvin, K)
First, you need to convert the temperature from Celsius to kelvin by adding 273.15:
T = 27°C + 273.15 = 300.15 K
Now, plug in the values:
P * (10^-3 m³) = (3 moles) * (8.314 J/(mol·K)) * (300.15 K)
Now, solve for P:
P = (3 * 8.314 * 300.15) / (10^-3)
P = 74786.69 Pa
So, the pressure of 3 moles of the ideal gas at 27°C with a volume of 10^-3 m³ is approximately 74,786.69 pascals.
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