PHYSICS
JAMB 2002 - Question 12
Physics 2002 JAMB Past Questions - Question 12: A particle in circular motion performs 30 oscillations in 6 seconds ts angular velocity is
Choose the correct answers from the options given.
A:
B:
C:
D:
Correct Answer
A
Explanation
w=2πF=2*π*30/6=10πrad/sTo find the angular velocity of a particle in circular motion, you can use the formula:
Angular velocity (ω) = (2π * Number of oscillations) / Time
In this case, the particle performs 30 oscillations in 6 seconds, so you can plug in these values into the formula:
Angular velocity (ω) = (2π * 30) / 6
Angular velocity (ω) = (60π) / 6
Now, simplify the expression:
Angular velocity (ω) = 10π radians per second
So, the angular velocity of the particle in circular motion is 10π radians per second.
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