PHYSICS
JAMB 2000 - Question 23
Physics 2000 JAMB Past Questions - Question 23: A travelling wave moving from left to right has an amplitude of 0.15 m. a frequency of 550 Hz and a wavelength of 0.01 m. The equation describing the wave is
A:
B:
C:
D:
Correct Answer
A
Explanation
The general wave equation is given by Y = sin A 2π/λ [x - vt]
= Sin A [(2π X)/λ - (2π vt)/λ]
thus if A = 0.15;λ = 0.01m; f = 550Hz
then V = f x λ = 550 x 0.01 = 5.50m/s
∴ Y = 0.15 sin [(2 x λ x X)/0.01 - (2 x λ x 5.5t)/0.01]
= 0.15 sin[200λX - 200 x λ x 5.5t]
∴ Y = 0.15 sin 200λ[x - 5.5t]
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