MATHEMATICS

JAMB 2018 - Question 37

Mathematics 2018 JAMB Past Questions - Question 37: Divide the L.C.M. of 48, 64 and 80 by their H.C.F.

Divide the L.C.M. of 48, 64 and 80 by their H.C.F.
A:
B:
C:
D:
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Correct Answer

D

Explanation

To solve this problem, we first need to find the LCM (Least Common Multiple) and HCF (Highest Common Factor) of the numbers 48, 64, and 80.First, let's find the LCM:The prime factorization of 48 is 2^4 * 3.The prime factorization of 64 is 2^6.The prime factorization of 80 is 2^4 * 5.The LCM is the product of the highest powers of all prime factors involved. Therefore, the LCM of 48, 64, and 80 is 2^6 * 3 * 5 = 960.Next, let's find the HCF:The common factors of 48, 64, and 80 are 1, 2, 4, 8, and 16.Therefore, the HCF of 48, 64, and 80 is 16.Now, we can divide the LCM by the HCF:960 ÷ 16 = 60.So, the result of dividing the LCM of 48, 64, and 80 by their HCF is 60.To solve this problem, we first need to find the LCM (Least Common Multiple) and HCF (Highest Common Factor) of the numbers 48, 64, and 80.First, let's find the LCM:The prime factorization of 48 is 2^4 * 3.The prime factorization of 64 is 2^6.The prime factorization of 80 is 2^4 * 5.The LCM is the product of the highest powers of all prime factors involved. Therefore, the LCM of 48, 64, and 80 is 2^6 * 3 * 5 = 960.Next, let's find the HCF:The common factors of 48, 64, and 80 are 1, 2, 4, 8, and 16.Therefore, the HCF of 48, 64, and 80 is 16.Now, we can divide the LCM by the HCF:960 ÷ 16 = 60.So, the result of dividing the LCM of 48, 64, and 80 by their HCF is 60.

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