MATHEMATICS
JAMB 2013 - Question 2
Mathematics 2013 JAMB Past Questions - Question 2: Find the value of 110111₂ +10100₂
A:
B:
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D:
Correct Answer
D
Explanation
110111+ >10100 1001011₂To find the sum of 110111₂ and 10100₂, we can perform binary addition.``` 110111+ 010100---------```Starting from the rightmost bit, we add the corresponding bits along with any carry:``` 110111+ 010100--------- 1000011```The sum is 1000011₂.Therefore, the value of 110111₂ + 10100₂ is 1000011₂, which is equivalent to 67 in decimal notation.
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