MATHEMATICS

JAMB 2013 - Question 14

Mathematics 2013 JAMB Past Questions - Question 14: P varies jointly as m and u ,and varies inversely as q.given that p=4 ,m=3 and u=2 when q=1,find the value of p when m=6,u=4 and q=8/5.

P varies jointly as m and u ,and varies inversely as q.given that p=4 ,m=3 and u=2 when q=1,find the value of p when m=6,u=4 and q=8/5.
A:
B:
C:
D:
Examkits App

Examkit's JAMB CBT App

Practice JAMB offline with our Online, PC and Mobile App

  • ✅ 25+ years of past questions (2000 to 2025)
  • ✅ Video solutions and explanation to questions
  • ✅ E-library
  • ✅ Study by topic
  • ✅ And more.

Correct Answer

A

Explanation

To solve this problem, we can use the concept of joint variation and inverse variation.We are given that P varies jointly as m and u, and inversely as q. This can be expressed as:P = k * (m * u) / qwhere k is the constant of variation.We can find the value of k by substituting the given values of P, m, u, and q into the equation:4 = k * (3 * 2) / 1Simplifying this equation, we have:4 = 6kDividing both sides by 6, we find:k = 4/6 = 2/3Now that we have the value of k, we can use it to find the value of P when m = 6, u = 4, and q = 8/5:P = (2/3) * (6 * 4) / (8/5)Simplifying this expression, we get:P = (2/3) * 24 / (8/5)  = (2/3) * (24 * 5) / 8  = (2/3) * 120 / 8  = (2/3) * 15  = 10Therefore, when m = 6, u = 4, and q = 8/5, the value of P is 10.

Frequently Asked Questions

Examkits is a JAMB CBT practice platform that provides over 20 years of past questions, Post UTME questions, and detailed video solutions to help students prepare for their exams.

You can practice JAMB past questions online, on Android, or on a desktop using the Examkits app. Just register on our website and choose your preferred device.

Yes. Our Android and Windows versions support offline usage. Once downloaded and activated, no internet is required to use most of the features.

Yes, Examkits provides detailed video explanations for all JAMB past questions from 2000 to 2024, helping students understand how to solve each problem.

Examkits offers free practice for some subjects. However, full access requires a one-time affordable activation fee for each version of the app.