MATHEMATICS
JAMB 2010 - Question 8
Mathematics 2010 JAMB Past Questions - Question 8: Given that log 2=0.3010 log 7=0.8451 ,Evaluate log 112.
A:
B:
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Correct Answer
B
Explanation
Given log₂ = 0.3010 log7 = 0.8451₄ i.e log112 = log2⁴ + log7 = 4log2 + log 7=(4 X 0.3010) + 0.8451 = 2.0491To evaluate log 112 using the given logarithmic values, we can use the properties of logarithms.First, let's express 112 as a product of prime factors: 112 = 2^4 * 7^1.Using the property log (a * b) = log a + log b, we can rewrite log 112 as:log 112 = log (2^4 * 7^1) = log (2^4) + log (7^1)Using the given logarithmic values, we substitute log 2 = 0.3010 and log 7 = 0.8451:log 112 = 4 * log 2 + log 7 = 4 * 0.3010 + 0.8451 = 1.2040 + 0.8451 = 2.0491Therefore, log 112 is approximately equal to 2.0491.
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