MATHEMATICS
JAMB 2010 - Question 4
Mathematics 2010 JAMB Past Questions - Question 4: A student measure a piece of rope and found that was 1.26m .if the actual length of the rope was 1.25m ,what was the percentage error in the measurement?
A:
B:
C:
D:
Correct Answer
D
Explanation
actual length of rope = 1.25mmeasured length of rope = 1.26mtherefore error = (1.26 -1.25)m = 0.01mtherefore percentage error = error /actual length x 100%= 0.01 / 1.25 x 100%= 0.80%To calculate the percentage error in the measurement, we can use the formula:Percentage Error = (|Measured Value - Actual Value| / Actual Value) * 100In this case, the measured value is 1.26m and the actual value is 1.25m. Plugging these values into the formula, we get:Percentage Error = (|1.26 - 1.25| / 1.25) * 100 = (0.01 / 1.25) * 100 = 0.008 * 100 = 0.8%Therefore, the percentage error in the measurement is 0.8%.
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