MATHEMATICS
JAMB 2008 - Question 43
Mathematics 2008 JAMB Past Questions - Question 43: What is the mean of the data t,2t-1,t-2,2t-1,4t and 2t+2?
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Correct Answer
D
Explanation
t+2t-1+t-2+2t-1+4t+2t+2 / 6= 12t -2 /6 = 12t /6 - 2/6= 2t - 1/3To find the mean of a set of data, we sum up all the values and divide by the number of values.In this case, we have the data: t, 2t-1, t-2, 2t-1, 4t, and 2t+2.The sum of the data is:t + (2t-1) + (t-2) + (2t-1) + 4t + (2t+2)Simplifying the expression:t + 2t - 1 + t - 2 + 2t - 1 + 4t + 2t + 2Combining like terms:10t - 2The number of values in the data set is 6.Therefore, the mean of the data is:(10t - 2) / 6Simplifying further, we have:Mean = (5t - 1) / 3So, the mean of the given data is (5t - 1) / 3.
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