MATHEMATICS

JAMB 2007 - Question 40

Mathematics 2007 JAMB Past Questions - Question 40: If the line 3y=4x-1 and qy=x+3 are parallel to each other ,the value of q is.

If the line 3y=4x-1 and qy=x+3 are parallel to each other ,the value of q is.
A:
B:
C:
D:
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Correct Answer

D

Explanation

To determine the value of q for which the lines 3y = 4x - 1 and qy = x + 3 are parallel, we need to compare their slopes.The slope of a line can be determined by rearranging the equation into slope-intercept form (y = mx + b), where m is the slope.For the line 3y = 4x - 1:Dividing both sides by 3, we get y = (4/3)x - 1/3.The slope of this line is 4/3.For the line qy = x + 3:Dividing both sides by q, we get y = (1/q)x + 3/q.The slope of this line is 1/q.Since the two lines are parallel, their slopes must be equal. Therefore, we have:4/3 = 1/qTo solve for q, we can cross-multiply:4q = 3Dividing both sides by 4, we get:q = 3/4Therefore, the value of q for which the lines 3y = 4x - 1 and qy = x + 3 are parallel is q = 3/4.

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