MATHEMATICS

JAMB 2007 - Question 37

Mathematics 2007 JAMB Past Questions - Question 37: The sum of the ages of musa and lawal is 28 years .After sharing a certain sum of money in the ratio of their ages ,musa gets N600 and Lawal N800. How old is lawal?

The sum of the ages of musa and lawal is 28 years .After sharing a certain sum of money in the ratio of their ages ,musa gets N600 and Lawal N800. How old is lawal?
A:
B:
C:
D:
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Correct Answer

B

Explanation

M + L = 28, M: L = 600 :800 = 3:4M /L = 3 / 4 M = 3 /4 Ltherefore 3 /4 L + L = 28 7L / 4 = 28therfore L = 4 x 28 / 7 = 16therfore Lawal is 16 years oldLet's assume Musa's age is x years and Lawal's age is y years.According to the given information, the sum of their ages is 28 years:x + y = 28 ...(1)After sharing a certain sum of money in the ratio of their ages, Musa gets N600 and Lawal gets N800:Musa's share / Lawal's share = Musa's age / Lawal's age600 / 800 = x / ySimplifying this equation, we get:3/4 = x / y ...(2)Now, we can solve the system of equations (1) and (2) to find the values of x and y.From equation (1), we can express x in terms of y:x = 28 - ySubstituting this value of x in equation (2):3/4 = (28 - y) / yCross-multiplying:3y = 4(28 - y)3y = 112 - 4y7y = 112y = 112 / 7y = 16Therefore, Lawal is 16 years old.

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