MATHEMATICS
JAMB 2006 - Question 2
Mathematics 2006 JAMB Past Questions - Question 2: A final examination requires that a student answer any 4 out of 6 questions.in how many ways can this be done?
A:
B:
C:
D:
Correct Answer
A
Explanation
To find the number of ways a student can answer any 4 out of 6 questions, we can use the combination formula.The number of ways to choose r items from a set of n items is given by the combination formula:C(n, r) = n! / (r!(n-r)!)In this case, we have 6 questions and the student needs to answer 4 of them. Therefore, we can calculate:C(6, 4) = 6! / (4!(6-4)!) = 6! / (4!2!) = (6 x 5 x 4 x 3 x 2 x 1) / ((4 x 3 x 2 x 1) x (2 x 1)) = (6 x 5) / (2 x 1) = 30 / 2 = 15Therefore, there are 15 ways for the student to answer any 4 out of the 6 questions.
Frequently Asked Questions
Examkits is a JAMB CBT practice platform that provides over 20 years of past questions, Post UTME questions, and detailed video solutions to help students prepare for their exams.
You can practice JAMB past questions online, on Android, or on a desktop using the Examkits app. Just register on our website and choose your preferred device.
Yes. Our Android and Windows versions support offline usage. Once downloaded and activated, no internet is required to use most of the features.
Yes, Examkits provides detailed video explanations for all JAMB past questions from 2000 to 2024, helping students understand how to solve each problem.
Examkits offers free practice for some subjects. However, full access requires a one-time affordable activation fee for each version of the app.