MATHEMATICS

JAMB 2005 - Question 13

Mathematics 2005 JAMB Past Questions - Question 13: Divide 6x² -13x + 5 by 2x-1

Divide 6x² -13x + 5 by 2x-1
A:
B:
C:
D:
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Correct Answer

B

Explanation

To divide the polynomial 6x² - 13x + 5 by 2x - 1, we can use polynomial long division.            3x - 2        _______________2x - 1 | 6x² - 13x + 5First, we divide the leading term of the dividend (6x²) by the leading term of the divisor (2x), which gives us 3x. We write this as the first term of the quotient.Next, we multiply the divisor (2x - 1) by the quotient term (3x) and subtract it from the dividend (6x² - 13x + 5).            3x - 2        _______________2x - 1 | 6x² - 13x + 5            - (6x² - 3x)        _______________                    -10x + 5Now, we bring down the next term from the dividend (-10x) and repeat the process.            3x - 2        _______________2x - 1 | 6x² - 13x + 5            - (6x² - 3x)        _______________                    -10x + 5                    - (-10x + 5)        _______________                            0Since the remainder is 0, we have successfully divided the polynomial.Therefore, the quotient is 3x - 5 and there is no remainder.

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