MATHEMATICS
JAMB 2004 - Question 46
Mathematics 2004 JAMB Past Questions - Question 46: In how many ways can 2 students be selected from a group of 4 students in a debating competition ?
A:
B:
C:
D:
Correct Answer
A
Explanation
To determine the number of ways to select 2 students from a group of 4 students for a debating competition, we can use the concept of combinations.The number of ways to select r items from a set of n items is given by the formula:C(n, r) = n! / (r!(n-r)!)In this case, we want to select 2 students from a group of 4 students, so we can calculate:C(4, 2) = 4! / (2!(4-2)!)Simplifying the expression:C(4, 2) = 4! / (2! * 2!)Calculating the factorials:4! = 4 * 3 * 2 * 1 = 242! = 2 * 1 = 2Substituting the values:C(4, 2) = 24 / (2 * 2) = 24 / 4 = 6Therefore, there are 10 ways to select 2 students from a group of 4 students for the debating competition.
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