MATHEMATICS
JAMB 2002 - Question 26
Mathematics 2002 JAMB Past Questions - Question 26: If x varies directly as √n and x=9 when n=9,find x when n=17/9
A:
B:
C:
D:
Correct Answer
D
Explanation
If x varies directly as √n, we can write the equation as x = k√n, where k is the constant of variation.To find the value of k, we can substitute the given values of x and n into the equation:9 = k√9Simplifying, we have:9 = 3kDividing both sides by 3, we find:k = 3Now that we have the value of k, we can use it to find x when n = 17/9:x = 3√(17/9)Simplifying further:x = 3 * (√17 / √9)Since √9 = 3, we have:x = 3 * (√17 / 3)The 3's cancel out, leaving us with:x = √17Therefore, when n = 17/9, x = √17.
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