MATHEMATICS
JAMB 2002 - Question 18
Mathematics 2002 JAMB Past Questions - Question 18: Find the maximum value of y in the equation y=1-2x-3x2
A:
B:
C:
D:
Correct Answer
D
Explanation
To find the maximum value of y in the equation y = 1 - 2x - 3x^2, we can use calculus. First, let's find the derivative of y with respect to x:dy/dx = -2 - 6xTo find the maximum value of y, we need to find the critical points where dy/dx = 0. Setting -2 - 6x = 0 and solving for x:-2 - 6x = 06x = -2x = -2/6x = -1/3Now, let's substitute this value of x back into the original equation to find the corresponding y-value:y = 1 - 2(-1/3) - 3(-1/3)^2y = 1 + 2/3 - 3/9y = 1 + 2/3 - 1/3y = 1 + 1/3y = 4/3Therefore, the maximum value of y in the equation y = 1 - 2x - 3x^2 is 4/3.
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