MATHEMATICS

JAMB 2000 - Question 42

Mathematics 2000 JAMB Past Questions - Question 42: if the mean of the numbers 0, x+2, 3x+6 and 4x +8 is 4, find their mean deviation

if the mean of the numbers 0, x+2, 3x+6 and 4x +8 is 4, find their mean deviation
if the mean of the numbers 0, x+2, 3x+6 and 4x +8 is 4, find their mean deviation
A:
B:
C:
D:
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Correct Answer

C

Explanation

check solution in the diagram aboveTo find the mean deviation of the numbers 0, x+2, 3x+6, and 4x+8, we first need to find the mean of these numbers.The mean is calculated by summing all the numbers and dividing by the total count.Mean = (0 + (x+2) + (3x+6) + (4x+8)) / 4Simplifying the expression, we get:Mean = (8x + 16) / 4Mean = 2x + 4We are given that the mean is 4, so we can set up the equation:2x + 4 = 4Solving for x, we get:2x = 0x = 0Now that we have found the value of x, we can substitute it back into the expressions to find the numbers:0 + 2 = 23(0) + 6 = 64(0) + 8 = 8The numbers are 0, 2, 6, and 8.To find the mean deviation, we need to calculate the absolute difference between each number and the mean, sum them up, and divide by the total count.Mean Deviation = (|0 - 4| + |2 - 4| + |6 - 4| + |8 - 4|) / 4Simplifying the expression, we get:Mean Deviation = (4 + 2 + 2 + 4) / 4Mean Deviation = 12 / 4Mean Deviation = 3Therefore, the mean deviation of the numbers 0, x+2, 3x+6, and 4x+8 is 3.

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