MATHEMATICS
JAMB 2000 - Question 33
Mathematics 2000 JAMB Past Questions - Question 33: A predator moves in a circle of radius 2 center (0,0) while a prey moves along the line y=x if 0=x=2 at which points will they meet?
A:
B:
C:
D:
Correct Answer
A
Explanation
check solution in the diagram aboveTo find the points at which the predator and prey will meet, we need to find the intersection points between the circle and the line y = x.The equation of the circle with radius 2 and center (0,0) is x^2 + y^2 = 4.Substituting y = x into the equation of the circle, we get:x^2 + (x)^2 = 42x^2 = 4x^2 = 2x = ±√2So, the x-coordinates of the intersection points are x = √2 and x = -√2.Substituting these values back into the equation y = x, we get the corresponding y-coordinates:For x = √2, y = √2For x = -√2, y = -√2Therefore, the points at which the predator and prey will meet are (√2, √2) and (-√2, -√2).
Frequently Asked Questions
Examkits is a JAMB CBT practice platform that provides over 20 years of past questions, Post UTME questions, and detailed video solutions to help students prepare for their exams.
You can practice JAMB past questions online, on Android, or on a desktop using the Examkits app. Just register on our website and choose your preferred device.
Yes. Our Android and Windows versions support offline usage. Once downloaded and activated, no internet is required to use most of the features.
Yes, Examkits provides detailed video explanations for all JAMB past questions from 2000 to 2024, helping students understand how to solve each problem.
Examkits offers free practice for some subjects. However, full access requires a one-time affordable activation fee for each version of the app.