BIOLOGY
JAMB 2023 - Question 3
Biology 2023 JAMB Past Questions - Question 3: The filaments of Spirogyra were put into equal volumes of sugar solutions X and Y. After 5 minutes, filaments from solution X had their cell contents rounded up while those from Y were unaffected. The experiment shows that
A:
B:
C:
D:
Correct Answer
A
Explanation
The experiment described suggests that solution X is hypertonic to the cell contents of Spirogyra, while solution Y is isotonic or hypotonic.Here's the breakdown:
- Filaments from Spirogyra were placed into equal volumes of sugar solutions X and Y.
- After 5 minutes, the cell contents of filaments from solution X rounded up, indicating water loss and plasmolysis due to a hypertonic environment. This means that solution X has a higher solute concentration compared to the cell contents of Spirogyra.
- Filaments from solution Y were unaffected, indicating that the concentration of solutes in solution Y is either equal to or lower than the concentration within the cell contents of Spirogyra. This suggests that solution Y is either isotonic or hypotonic to the cell contents of Spirogyra.
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