Physics 2008 JAMB Past Questions - Question 1: The dimension of electromotive force are

Correct Answer

A

Explanation

The dimension of electromotive force (EMF) is voltage or electric potential difference. In the International System of Units (SI), the dimension of EMF is measured in volts (V). The SI unit of voltage, the volt, is equivalent to one joule per coulomb (1 V = 1 J/C). Therefore, the dimension of EMF can be expressed as:

[EMF] = [Voltage] = [Energy] / [Charge] = [Joule] / [Coulomb] = [M^2 * kg / s^2] / [A] = [M^2 * kg * s^-3 * A^-1]

Where:
- [EMF] represents the dimension of electromotive force.
- [Voltage] is the dimension of voltage in volts (V).
- [Energy] is the dimension of energy in joules (J).
- [Charge] is the dimension of charge in coulombs (C).
- M represents meters (length).
- kg represents kilograms (mass).
- s represents seconds (time).
- A represents amperes (electric current).

So, the dimension of electromotive force includes dimensions of length, mass, time, and electric current, and is represented as [M^2 * kg * s^-3 * A^-1].