PHYSICS

JAMB 2017 - Question 9

Physics 2017 JAMB Past Questions - Question 9: Calculate the electric field intensity between two plates of potential difference 6.5V when separated by a distance of 35cm.

Choose the correct answers from the options given.
Calculate the electric field intensity between two plates of potential difference 6.5V when separated by a distance of 35cm.
A:
B:
C:
D:
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Correct Answer

A

Explanation

Electric field intensity,E = V = 6.5 = 650 = 18.57Nc1 D 0.35 350To calculate the electric field intensity between two plates, we can use the formula:

Electric field intensity (E) = Potential difference (V) / Distance between plates (d)

Given:
Potential difference (V) = 6.5V
Distance between plates (d) = 35cm = 0.35m

Using the formula, we can substitute the given values:

E = 6.5V / 0.35m

Calculating the result:

E ≈ 18.57 V/m

Therefore, the electric field intensity between the two plates is approximately 18.57 V/m.