MATHEMATICS
JAMB 2006 - Question 9
Mathematics 2006 JAMB Past Questions - Question 9: For what value of n is º¹C‚ƒ = 4 (C‚ƒ)?
Choose the most appropriate option for the gap .
A:
B:
C:
D:
Correct Answer
D
Explanation
º¹C₃ = (n+1)!/(n+1) -3)!3! = (n+1) (n) (n-1)(n-2)!/(n-2)! 3X2= n(n+1)(n-1) /6 4(C₃) = n(n-1)(n-2)/3 , n(n+1) (n-1)/6 = 2n(n-1) (n-2)/3 → n+1/6 = 2(n-2)/3→ 3n +3 = 12n – 24 → 27-9n→n = 3

