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MATHEMATICS

JAMB 2015 - Question 7

Mathematics 2015 JAMB Past Questions - Question 7: If x+1 is a factor of x3+3x2+mx+4 ,find the value of m.

If x+1 is a factor of x3+3x2+mx+4 ,find the value of m.

A: 8

B: 6

C: -8

D: -6

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Correct Answer

Explanation

x+1=0x=-1(-1)3+3(-1)2+m(-1)+4=0-1+3-m+4=06-m=0m=6To find the value of m when x+1 is a factor of x^3 + 3x^2 + mx + 4, we can use the factor theorem. According to the factor theorem, if x+1 is a factor of the given polynomial, then the polynomial evaluated at x=-1 should equal 0.So, substituting x=-1 into the polynomial, we get:(-1)^3 + 3(-1)^2 + m(-1) + 4 = 0-1 + 3 - m + 4 = 06 - m = 0m = 6Therefore, the value of m is 6.