PHYSICS

JAMB 2004 - Question 49

Physics 2004 JAMB Past Questions - Question 49: A cell whose internal resistance is 0.5ohms delivers a current of 4A to an external resistor the lost voltage of the cell is.

Choose the correct answers from the options given.
A cell whose internal resistance is 0.5ohms delivers a current of 4A to an external resistor the lost voltage of the cell is.
A:
B:
C:
D:
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Correct Answer

D

Explanation

To find the lost voltage of the cell, you can use Ohm's law, which relates voltage (V), current (I), and resistance (R) in an electric circuit. Ohm's law is given by:

V = I * R

In this case, the internal resistance of the cell is 0.5 ohms, and it delivers a current of 4 amperes to an external resistor. The lost voltage of the cell is the voltage drop across its internal resistance. So, you can calculate it as follows:

Lost Voltage (V) = Current (I) * Internal Resistance (R)
Lost Voltage (V) = 4 A * 0.5 ohms
Lost Voltage (V) = 2 volts

Therefore, the lost voltage of the cell is 2 volts.