Physics 2003 JAMB Past Questions - Question 48: An electron makes a transition from a certain energy level Ek to the ground state E0. If the frequency of emission is 8.0 x 10¹´Hz, the energy emitted is

Correct Answer

B

Explanation

atomic emission and absorption of energy is usually in packets referred to as photo or quantum of energy; of magnitude E = hf, where f is the frequency, and h is the Planck's' constant.energy emitted = hf = 6.6x10-34 x 8.0x10-14 = 5.28x10-19jThe energy emitted when an electron makes a transition from a higher energy level (Ek) to a lower energy level (E0) can be calculated using the formula:

E = hf

Where:
E is the energy emitted,
h is Planck's constant (approximately 6.626 x 10^-34 J·s),
f is the frequency of emission.

Given the frequency (f) as 8.0 x 10^14 Hz, you can calculate the energy emitted as follows:

E = (6.626 x 10^-34 J·s) * (8.0 x 10^14 Hz)

E ≈ 5.3 x 10^-19 Joules

So, the energy emitted during the transition is approximately 5.3 x 10^-19 Joules.