MATHEMATICS

JAMB 2000 - Question 48

Mathematics 2000 JAMB Past Questions - Question 48: Find the sum of the range and the mode of the set of number 10,5,10,9,8,7,7,10,8,10,8,4,6,,9,10,9,10,9,7,10,6,5.

Find the sum of the range and the mode of the set of number 10,5,10,9,8,7,7,10,8,10,8,4,6,,9,10,9,10,9,7,10,6,5.
A:
B:
C:
D:
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Correct Answer

A

Explanation

Range = highest score - lowest score = 10 - 4 = 6mode of distribution (scores) = 10 (higest occurencies);total (sum) = Range + mode = 10 +6 = 16To find the sum of the range and the mode of the given set of numbers, let's first determine the range and the mode.Range:The range is the difference between the maximum and minimum values in a set of numbers.Given set of numbers: 10, 5, 10, 9, 8, 7, 7, 10, 8, 10, 8, 4, 6, 9, 10, 9, 10, 9, 7, 10, 6, 5Maximum value: 10Minimum value: 4Range = Maximum value - Minimum value = 10 - 4 = 6Mode:The mode is the value that appears most frequently in a set of numbers.Given set of numbers: 10, 5, 10, 9, 8, 7, 7, 10, 8, 10, 8, 4, 6, 9, 10, 9, 10, 9, 7, 10, 6, 5The number 10 appears most frequently, occurring 6 times. Therefore, the mode is 10.Now, let's find the sum of the range and the mode:Sum = Range + Mode = 6 + 10 = 16Therefore, the sum of the range and the mode of the given set of numbers is 16.