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PHYSICS

JAMB 2010 - Question 47

Physics 2010 JAMB Past Questions - Question 47: The ground state energy for a hydrogen atom is 5.44 x 10¹J. I f an electron drops from zero energy to the ground state, calculate the frequency of the emitted radiation.

Choose the correct answers from the options given.

The ground state energy for a hydrogen atom is 5.44 x 10¹J. I f an electron drops from zero energy to the ground state, calculate the frequency of the emitted radiation.

A: 2.0 x 10¹Hz

B: 2.0 x 10¹Hz

C: 5.0 x 10¹Hz

D: 5.0 x 10¹Hz

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Correct Answer

Explanation

?E = hf
f = (?E)/h = (5.44 x 10-19)/6.6 x 10-34 = 8.24 x 1014