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PHYSICS

JAMB 2008 - Question 44

Physics 2008 JAMB Past Questions - Question 44: Given three indictors of inductance 5mH,10mH and 20mH connected in series the effective inductance is

Choose the correct answers from the options given.

Given three indictors of inductance 5mH,10mH and 20mH connected in series the effective inductance is

A: 0.35mH

B: 3.50mH

C: 2.90mH

D: 35.00mH

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Correct Answer

Explanation

When inductors are connected in series, their total inductance is the sum of their individual inductances. So, for three inductors with inductances of 5mH, 10mH, and 20mH connected in series, the effective inductance (L_total) is:

L_total = 5mH + 10mH + 20mH

L_total = 35mH

So, the effective inductance of these three inductors connected in series is 35 milliHenries (mH).