MATHEMATICS
JAMB 2011 - Question 43
Mathematics 2011 JAMB Past Questions - Question 43: The sum of four consecutive integers is 34. find the least of these numbers .
A:
B:
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Correct Answer
A
Explanation
Let the numbers be a, a+1, a+2,a+3therefore a+a+1+a+2+a+3=344a+6=344a = 34 -6 4a = 28a = 28/4 = 7The least of these numbers is a =7Let's represent the four consecutive integers as x, x+1, x+2, and x+3.According to the problem, the sum of these four consecutive integers is 34:x + (x+1) + (x+2) + (x+3) = 34Simplifying the equation:4x + 6 = 34Subtracting 6 from both sides:4x = 28Dividing both sides by 4:x = 7Therefore, the least of these four consecutive integers is 7.

