Physics 2001 JAMB Past Questions - Question 42: Which of the following metals will provide the greatest shield against ionizing radiation?

Correct Answer

D

Explanation

When it comes to shielding against ionizing radiation, such as gamma rays or X-rays, the effectiveness of a metal depends on its density and atomic number. Generally, metals with higher atomic numbers and greater density provide better shielding against ionizing radiation.

Out of the metals typically available, lead (Pb) is often considered one of the most effective materials for shielding against ionizing radiation. Lead has a high atomic number (82) and is dense, which makes it an excellent choice for radiation protection in various applications, including radiology, nuclear facilities, and other settings where radiation exposure needs to be minimized.

Other metals with high atomic numbers and good shielding properties include tungsten (W) and bismuth (Bi). However, lead remains a common choice due to its affordability, availability, and effectiveness.