MATHEMATICS

JAMB 2007 - Question 42

Mathematics 2007 JAMB Past Questions - Question 42: The volume of a hemisphere bowl is 718 ⅔ cm³ find the Radius.

The volume of a hemisphere bowl is 718 ⅔ cm³ find the Radius. <π= 22/7>
A:
B:
C:
D:
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Correct Answer

C

Explanation

volume of a hemisphere bowl = ⅔ πr³ = 718 ⅔ → r³ = 2156/3 X 3/2 X 7/2 = 539X 7 /11 = 343 i.e r = 3 √343 = 7cm To find the radius of the hemisphere bowl, we can use the formula for the volume of a hemisphere:V = (2/3)πr³Given that the volume of the hemisphere bowl is 718 ⅔ cm³, we can substitute this value into the formula:718 ⅔ = (2/3)(22/7)r³To simplify the equation, we can convert the mixed fraction 718 ⅔ to an improper fraction:718 ⅔ = (3 * 718 + 2) / 3 = 2156/3Substituting this value into the equation:2156/3 = (2/3)(22/7)r³To solve for r³, we can multiply both sides by (3/2)(7/22):r³ = (2156/3) * (3/2) * (7/22)Simplifying:r³ = 308Taking the cube root of both sides:r = ∛308Using a calculator, we find that the cube root of 308 is approximately 6.83.Therefore, the radius of the hemisphere bowl is approximately 6.83 cm.