Physics 2021 JAMB Past Questions - Question 4:  A charge of 30μC experiences a force of 60N at a certain point. The electric field intensity due to the charge is

Correct Answer

D

Explanation

The electric field intensity (\(E\)) due to a point charge can be calculated using the formula:

\[E = \frac{F}{q}\]

Where:
\(E\) = Electric field intensity
\(F\) = Force experienced by the charge
\(q\) = Magnitude of the charge

In this case, the force experienced by the charge is 60N and the magnitude of the charge is 30μC (which is \(30 \times 10^{-6}\) C).

Plugging these values into the formula:

\[E = \frac{60}{30 \times 10^{-6}} = 2 \times 10^6 N/C\]

So, the electric field intensity due to the charge is \(2 \times 10^6 N/C\).