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MATHEMATICS

JAMB 2003 - Question 4

Mathematics 2003 JAMB Past Questions - Question 4: Find (1/0.06 + 1/0.042) ¯1 correct to 2 dec. places

Find (1/0.06 + 1/0.042) ¯1 correct to 2 dec. places

A: 1.43

B: 1.53

C: 3.14

D: 4.42

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Correct Answer

Explanation

To find the value of (1/0.06 + 1/0.042) ¯1, we need to evaluate the expression and round the result to two decimal places.Let's calculate it step by step:1/0.06 + 1/0.042 = 16.666... + 23.809...Adding these two values, we get:16.666... + 23.809... = 40.475...Now, rounding this result to two decimal places, we have:(1/0.06 + 1/0.042) ¯1 ≈ 40.48Therefore, the value of (1/0.06 + 1/0.042) ¯1, correct to two decimal places, is approximately 40.48.