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PHYSICS

JAMB 2003 - Question 39

Physics 2003 JAMB Past Questions - Question 39: In the calibration of an ammeter using Faraday's laws of electrolysis, the ammeter reading is kept constant at 1.20A. If 0.990g of copper is deposited in 40 minutes, the correction to be applied to the ammeter is

Choose the correct answers from the options given.

In the calibration of an ammeter using Faraday's laws of electrolysis, the ammeter reading is kept constant at 1.20A. If 0.990g of copper is deposited in 40 minutes, the correction to be applied to the ammeter is

A: 0.03A

B: 0.04A

C: 0.05A

D: 0.06A

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Correct Answer

Explanation

From faraday's law of electrolysis

M = I t Z
0.990 = I x (40 x 60) x 3.3 x 10^-4

?0.990/2400×3.3×10^−4 = 1.25AThus the correction to be made = 1.25 − 1.20 = 0.05A