Mathematics 2018 JAMB Past Questions - Question 39: A man's initial salary is #540.00 a month and increases after each period of six months by #36.00 a month.Find his salary in the eight month of the third year.

Correct Answer

C

Explanation

Initial salary = 540Increment = 36 (every six months)Period of increment = 2yrs and six monthsAmount (increment) = 36x5 = 180The man's new salary = 540 + = 180=720.00To find the man's salary in the eighth month of the third year, we can use the formula for an arithmetic sequence:\[ \text{Salary} = \text{Initial Salary} + (\text{Number of Periods} - 1) \times \text{Increase in Salary} \]The initial salary is #540.00, and the increase after each period of six months is #36.00.First, let's find the number of periods in three years. Since each period is six months, there are 3 years * 2 periods/year = 6 periods.Now, we can calculate the salary in the eighth month of the third year:\[ \text{Salary} = 540 + (6 - 1) \times 36 \]\[ \text{Salary} = 540 + 5 \times 36 \]\[ \text{Salary} = 540 + 180 \]\[ \text{Salary} = 720 \]So, the man's salary in the eighth month of the third year is #720.00.