MATHEMATICS

JAMB 2002 - Question 39

Mathematics 2002 JAMB Past Questions - Question 39: Find the value of & if the line 2y-&x+4=0 is perpendicular to the line y+1/4x-7=0

Find the value of & if the line 2y-&x+4=0 is perpendicular to the line y+1/4x-7=0
A:
B:
C:
D:
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Correct Answer

C

Explanation

To find the value of &, we need to determine the slope of the line 2y - &x + 4 = 0 and the slope of the line y + (1/4)x - 7 = 0.The given line y + (1/4)x - 7 = 0 is in the form y = mx + c, where m is the slope of the line. Comparing this equation to the standard form y = mx + c, we can see that the slope of this line is (1/4).For two lines to be perpendicular, the product of their slopes must be -1. Therefore, the slope of the line 2y - &x + 4 = 0 is the negative reciprocal of (1/4).So, (-&/2) * (1/4) = -1Simplifying the equation:-&/8 = -1Multiplying both sides by 8:-& = -8Dividing both sides by -1:& = 8Therefore, the value of & is 8.